Question

one of the zero of 2x²-3x-5 ​

Answer 1

2x² - 3x - 5

By splitting the mid term,

= 2x² - (5 - 2)x - 5

= 2x² - 5x + 2x - 5

= x(2x - 5) + 1(2x - 5)

= (2x - 5)(x + 1)

So, the zeroes are:

1) (2x - 5)(x + 1) = 0

⇒ 2x - 5 = 0 ⇒ x = 5/2

2) (2x - 5)(x + 1) = 0

⇒ x + 1 = 0 ⇒ x = - 1

∴ The zeroes are (- 1) and (5/2).

Answer 2

Step-by-step explanation:

• 2x^2-3x-5 = 2x^2+2x-5x-5
• =2x(x+1)- 5(x+1)
• (2x+5)(x+1)
• 2x+5=0 x+1=0
• 2x=-5 x=-1
• x=-5/2