Question

one of the zeroes of the polynomial 2 x2+7x-4 is

Answer 1

Answer:

Let p (x) = 2x2 + 7x-4

= 2x2 + 8x-x-4 [by splitting middle term]

= 2x(x+ 4)-1(x+ 4)

= (2x-1)(x+ 4)

For zeroes of p(x), put p(x) = 0 ⇒ (2x -1) (x + 4) = 0

⇒ 2x-1 = 0 and x+4 = 0

⇒ x = 1/2 and x = -4

Hence, one of the zeroes of the polynomial p(x) is 1/2.

Step-by-step explanation:

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