Question

One of the zeroes of the polynomial 35x^2 – 9x – 18 is (i) 3/5 (ii) -5/2 (iii) 6/7 (iv) 7/6

Answer 1

put all the four values and the value for which the polynomial turns out to be zero, is it's zero

Answer 2

Given:

$\bold{35x^2-9x -18}$

To Find:

zeroes =?

Solution:

$\bold{35x^2-9x -18=0}$

$\to 35x^2-(30-21)x-18=0\\\\\to 35x^2-30x+21x-18=0\\\\\to 5x(7x-6)+3(7x-6)=0\\\\\to (7x-6)(5x+3)=0\\\\\to 7x-6=0 \ \ \ \ \ and \ \ \ \ \ \ 5x+3=0\\\\\to x=\frac{6}{7} \ \ \ \ \ and \ \ \ \ \ \ x=- \frac{3}{5}$

The zeros value is $\frac{6}{7}$ which is "option (iii)".