Question

one of the zeros of the polynomial 2x^2+7x-4 is ​

Answer 1

Step-by-step explanation:

2x²+7x-4 = 2x² +8x-x-4=0

2x(x+4)-1(x+4)=0

(2x-1)(x+4)=0

First (2x-1)=0

2x=1

x=1/2

Second x+4=0

x=(-4)

So the zeroes are:- 1/2 , -4