Question

One of the zeros of the polynomial 2xsquare+9x-5 is

Answer 1

Answer:

$\frac{1}{2} , - 5$

Step-by-step explanation:

$2 {x}^{2} + 9x - 5 = 0$

$2{x}^{2} + 10x - x - 5 = 0$

$2x(x + 5) - 1(x + 5)$

$(2x - 1)(x + 5)$

$x = \frac{1}{2}$

$x = - 5$

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Answer 2

ANSWER:

• One of the zeros of polynomial P(x) can be (-5) or 1/2.

GIVEN:

• P(x) = 2x²+9x-5

TO FIND:

• Factorise the above expression.

SOLUTION:

=> 2x²+9x-5 = 0

=> 2x²+10x-x-5 = 0

=> (2x²+10x)+(-x-5) = 0

=> 2x(x+5) -1(x+5) = 0

=> (x+5)(2x-1) = 0

Either x+5 = 0

=> x = (-5)

Either (2x-1) = 0

=> 2x = 1

=> x = 1/2

One of the zeros of polynomial P(x) can be (-5) or 1/2.

NOTE:

Some important formulas:

(a+b)² = a²+b²+2ab

(a-b)² = a²+b²-2ab

(a+b)(a-b) = a²-b²

(a+b)³ = a³+b³+3ab(a+b)

(a-b)³ = a³-b³-3ab(a-b)

a³+b³ = (a+b)(a²+b²-ab)

a³-b³ = (a-b)(a²+b²+ab)

(a+b)² = (a-b)²+4ab

(a-b)² = (a+b)²-4ab