Question

one
of the zeros of the polynomial
P(x)= x²-x+ (k + 2) is 3, then the value of k is ?
​

Answer 1

Step-by-step explanation:

p(3)= 3*3 - 3 + k + 2 = 0

=> 9-3+2+k=0

=> 8 + k = 0

=> k = -8

Answer 2

Answer:

if one of zero is 3 of this equation

then 3^2-3+ (k+2) = 0. ...eq1 (replacing x by 3)

by simplifying equation we get 9 - 3 + (k+2) = 0

6 + (k+2)= 0

both side subtracting by 6

k+2= -6

both side subtracting by 2

we get. k+2-2= -6 -2

hence k =-8 for verifying we will put this value in eq 1

hence. 3^2 - 3 + (k+2) =0

9-3+(-8 + 2) = 0

6 + ( -6) = 0

6 - 6 = 0

0 = 0

I hope this answer is helpful for you