Question

One of to the two digits of a two digit is three times the other digit, if you interchange the of its two digit number and add the resulting number to the original number, you get 88.what is original number.? ​

Answer 1

AnswEr :

62.

$\bf{\green{\underline{\underline{\sf{Given\::}}}}}$

One of the two digits of a two digit is three times the other digit, if you interchange the of it's two digit number and add the resulting number to the original number you get 88.

$\bf{\red{\underline{\underline{\sf{To\:find\::}}}}}$

The original number.

$\bf{\purple{\underline{\underline{\bf{Explanation\::}}}}}$

Let the ten's place be 3r

Let the one's place be r

$\underbrace{\bf{Original\:number\:=10(3r)+r}}\\\\\underbrace{\bf{Reversed\:number\:=10(r)+3r}}$

$\bf{\red{\underline{\underline{\tt{A.T.Q.\::}}}}}$

$\dashrightarrow\tt{10(3r)+r+10(r)+3r=88}\\\\\\\dashrightarrow\tt{30r+r+10r+3r=88}\\\\\\\dashrightarrow\tt{31r+13r=88}\\\\\\\dashrightarrow\tt{44r=88}\\\\\\\dashrightarrow\tt{r=\cancel{\dfrac{88}{44} }}\\\\\\\dashrightarrow\tt{\purple{r=2}}$

Thus,

$\bf{\orange{\underline{\sf{The\:original\:number=10(3r)+r=10*3(2)+2=60+2=62.}}}}$

Answer 2

${\boxed{\mathtt{\purple{GIVEN}}}}$

• We have a two digit number .
• One digit is thrice of the other digit .
• The sum of the given digit and it's interchange is equals to 88 .

${\boxed{\mathtt{\purple{To \: Find}}}}$

• The original digit .

${\boxed{\mathtt{\purple{Solution}}}}$

➾ Let's assume that the tens place digit of the number is x .

And we are given that 2nd digit is thrice of 1st ,So

➾ Ones place digit = 3x

Sum of our original number is 10x +3x = 13x .

➾ On interchanging the digits .

Sum of interchanged number is 10(3x) + x = 31x

➾ Sum of these two digits = 88

➾ 13 x + 31 x = 88

➾ 44 x = 88

➾44 x = 44(2)

${\boxed{\mathtt{\red{ \:x \:= \:2 }}}}$

So the original number will :-

➾ 10 x + 3x

➾ 20 + 6

${\boxed{\mathtt{\red{ \:26 \:or\: 62 }}}}$