Question

One of two digits of a two digit number is twice the other digit .If you interchange the digits of two digit number and add the resulting number to the original number, you get 66. What is the original number?

Answer 1

Answer:

42

Step-by-step explanation:

Let one of the two digit number be x

we are giving that one of the two digit of a two digit number is

twice the other digit.

then, other digit =2x

then the number=10(x) + 2x

add the given number to the original number you get 66

10(2x) + x + 10(x) + 2x =66

20x + x + 10x +2x =66

33x = 66

x = 66÷33

x = 2

the original number = 10(2x) + x = 10(2×2) + 2 = 42

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Answer 2

Hope it helps...........