Question

One of two digits of a two digit number is twice the other digit .If you interchange the digits of two digit number and add the resulting number to the original number, you get 66. What is the original number?

Answer 1

Answer:

80 the original number= 10 (2x) +x

=10(2 multiply by 2) +2 =42

Hence the number is 42

Solution is attached

Hope it helps you

Answer 2

Step-by-step explanation:

The answer to the question is ‘26′ or ‘62′.

Let a digit be x (no matter units place or tens digit place) the the other digit will be 3x. Since 3x has to be a single-digit non-zero no. so x can only be either 1,2 or 3.

So the no. is (let it be ‘a’) a= x _3x (Now assuming x to be tens digit..You can also take it as units digit).

Then according to the question:

interchanged no. (let it be ‘b’) b= 3x_x.

now,

a+b=88 ……..(Given)

Since x can only be 1,2 or 3.

so addition would take no carry on.

so a+b=4x_4x=88.

comparing both places:

4x=8

and 4x=8.

(both equations are same)

so x=2.

So no. is either 26 or 62.

You can also see a=10*x+3x=13x

(As a 2-digit no. is of the form 10a+b,where both a,b are single digit no.s ‘a’ not equal to 0. )

similarly b=10*3x+x=31x

a+b=44x=88.

x=2.

so a=26 (or 62 according to what you have taken as tens digit.)

THANK YOU.