Question

One one of the two digit of a two digit number is three times the other digit if you interchange the digits of the two digit number and add the resulting to the original number you will get 88 what is the original number ?

Answer 1

Solution:

Let us consider the digit at tens place be x then digit at ones place will be 3x

Original two-digit number = $10x+3x$

After interchanging the digits, the new number = $30x+x$

According to the question,

$(30x+x)+(10x+3x)=88\\\implies 31x+13x=88\\\implies 44x=88$

Now, let's find the value of x

$\implies x=\frac{88}{44} \\\implies x=2$

Original number = $10x+3x=13x=13 \times 2 = \boxed{26}$

Answer 2

Answer:

$\huge\Large\underline\mathtt\pink{Step-by-step explanation:-}$

$\huge\Large\underline\mathtt\pink{Given :-}$

One of the two digits of a two digit number is three times the other digit.

If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88.

$\huge\Large\underline\mathtt\pink{Find :-}$

The Number

$\huge\Large\underline\mathtt\pink{Solution:-}$

Let the digits at tens place be x.

And ones place be 3x .

Original Number = 10x + 3x = 13x

Number after interchanging = 10 × 3x + x = 30x + x = 31x

$\huge\Large\underline\mathtt\pink{According to the Question,:-}$

⇒ Original number + New number = 88

⇒ 13x + 31x = 88

⇒ 44x = 88

⇒ x = 88/44

⇒ x = 2

Original Number = 13x = 13 × 2 = 26

Therefore, by considering the tens place and ones place as 3x and x.

Therefore, by considering the tens place and ones place as 3x and x.The two digit number obtained is 62.

Therefore, by considering the tens place and ones place as 3x and x.The two digit number obtained is 62.Hence, the two-digit number may be 26 or 62.

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