one parallel sides of a Trapezium is double the other the distance between the parallel side is on third of the smaller parallel sides find the length of the parallel sides of the trapezium if this area is 98
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let the smaller side be x
other side= 2x
height = x/3
area of trap = 98
1/2(x+2x)× x/3 = 98
1/2 × 3x × x/3 = 98
x²/2 = 98
x²= 98×2
x²= 196
x =√196
x =√14×14
x = 14
thus, smaller side = x =14
other side = 2x = 2×14 = 28
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