Question

One person borrow ₹4000 and agrees to repay with a total interest of ₹ 500 in 10 instalment . Each instalment being less than the preceding instalment by ₹ 10. what should be the first and the last instalment?​

Answer 1

Answer:

ANSWER is 459 & 369

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Sn=4000+500

=4500

d= -10

n = 10

Sn=n/2[2a+(n-1)d]

S10 = 10/2[2a+(10-1)-10]

4500=5[2a-90]

4500/5=2a-90

900=2a-90

990=2a

a=495

Tn=a+(n-1)d

T10=495+(10-1)-10

T10=495-90

T10=405

First installment=495

Last installment=405