One person borrows 4000rupees and agrees to repay with total interest of 500 rupees in 10 installment. Each installment being less than the preceding installment by 10 rupees. What should be the first and last installment?
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Answer:
Sn=n/2(2a+(n-1)d)
4500=10/2(2a+(9)(-10)
4500=5(2a-90)
900=2a-90
a=495
4500 =n/2(a+l)
=5(495+l)
l=405
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