Question

one person borrows rs.4000 and agrees to repay with total interest rs500 in 10 instalment.each instalment being less than the preceding instalment by rs.10 .what should be the first and last instalments?

Answer 1

Answer:

total amount paid=₹4000+₹500=₹4500

Sn=4500

n=10

each instalment less than preceding by ₹10=d=-10

by formula

Sn=n/2[2a+(n-1)d

4500=10/2[2a+(10-1)-10

4500×2/10=2a+9(-10)

900=2a-90

900+90=2a

990/2=a

a=495

first instalment=a=495

now by using formula

tn=a+(n-1)d

t10=495+(10-1)-10

t10=495+9(-10)

t10=495-90

t10=405

Last instalment=t10=405

Answer 2

Answer:

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