Question

One person buys a table and a chair for 500 rupees and sells the chair at 10% loss and the chair for 10% profit. Then the total profit is 10 rupees. How much money is the purchase price of the table??​

Answer 1

Answer:

cost price of table = 200

cost price of chair = 300

Step-by-step explanation:

let the cost price of table be x

the cost price of chair be y

total cost of table and chair x + y = 500

selling price of table is x - 10x/100

since loss is 10%

$\frac{100x - 10x}{100} \\ = \frac{90x}{100}$

selling price of chair is y + 10y/100

since profit is 10%

$\frac{100y + 10y}{100} \\ = \frac{110y}{100}$

total selling price is 510

since total profit earned is 10

$\frac{90x}{100} + \frac{110y}{100} = 510 \\ \frac{90x + 110y}{100} = 510 \\ 90x + 110y = 51000 \\ 9x + 11y = 5100$

multiply x + y = 500 with 11

11x + 11y = 5500

subtract the equation

11x + 11y = 5500

9x + 11y = 5100

2x = 400

x = 400/2

x = 200

substitute x = 200 in equ x + y = 500

200 + y = 500

y = 500 - 200

y = 300

therefore the cost price of table = x = 200

the cost price of chair = y = 300

hope you get your answer