Question

one person moving with 40km per one hour if his speed is increase 50 ℅ .how much time he take for 330 km​

Answer 1

Answer:

$\huge\star \underline{ \boxed{ \purple{Answer}}}\star$

Time taken to cover the distance of 330km =

$\sf{4\:hours\:12\:min's}$

Step-by-step explanation:

Given :-

s = 40km/hr

d = 330 km

and,

speed increases by 50%

To Find :-

Time taken to cover 330 km.

Solution :-

➝$\sf{s_1}$= 40km/hr

➝t = 1 hr

➝d = ?

➝$\sf{d\:=\:s_1\:\times\:t}$

$\sf\green{Putting\:values}$

➝$\sf{d\:=\:40\:\times\:1}$

➝$\sf{d\:=\:40\:km}$

$\sf\green{New\:Speed\::-}$

➝$\sf{s_2\:=\:40\:\times\:\cancel\frac{100}{50}\:2}$

➝$\sf\green{Now\:calculating\:time\:taken\:to\:cover\:330km\::-}$

➝$\sf{d\:=\:330km}$

➝$\sf{t\:=\:?}$

➝$\sf{s_2\:=\:\frac{d}{t}}$

➝$\sf{t\:=\:\frac{d}{s_2}}$

➝$\sf{t\:=\:\cancel\frac{330}{80}\:4.12}$

➝$\sf{t\:=\:4hr\:12min\:(approx.)}$

$\Large\sf\red{Hence,}$

He will take 4 hr & 12 min to cover 330km.

$\huge\mathfrak\pink{Hope \: it \: helps \: you}$

$\huge\mathfrak\pink{friend}$

Answer 2

Given,

Speed (s1) = 40km/h

Time (t1) = 15 mins = (15/60) hr

Distance d1 = (s1 × t1) = 40 × (15/60) = 10 km

WE KNOW THAT,

Speed (s2) = 60 km/h

Time (t2) = 15 min = (15/60) hour

Distance (d2) = (s2 × t2) = 60 × (15/60) = 15 km

Total distance (d) = (d1 + d2) = 10 km + 15 km = 25 km

$\mathcal { HOPE \: \: \: IT \: \: \: HELPS}$