one person pays rs. 405 bus fare for three adults from place a to place b and one adult place a to place c another person pays rs. 620 as bus fare from place a to place b and three adults from place a to place c find the bus fare for places and b between place a and c
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I guess there are some mistakes in the question which need to be rectified to get a proper answer. Hence, I am making the question as follows:
" One person pays Rs. 405 bus fare for three adults from place A to place B and one adult place A to place C. Another person pays Rs. 620 as bus fare for two adults from place A to place B and three adults from place A to place C. Find the bus fare for travelling from place A to place B and C.
Let the cost of each bus ticket from place A to place B be 'x' and the cost from place A to place C be 'y'.
From the data given, we can form the following equations:
3x + 1y = 405 -------(1)
2x + 3y = 620 -------(2)
Multiplying the first equation by 3, we get
9x + 3y = 1215 --------(3)
Subtracting (2) from (3), we get
7x = 1215-620
7x = 595
x= 85
Substituting the value of x in (1), we get
3(85) + y = 405
y = 405 - 255
y= 150
Thus, the bus fare for travelling from A to B is Rs. 85 and the fare from A to C is Rs. 150.
" One person pays Rs. 405 bus fare for three adults from place A to place B and one adult place A to place C. Another person pays Rs. 620 as bus fare for two adults from place A to place B and three adults from place A to place C. Find the bus fare for travelling from place A to place B and C.
Let the cost of each bus ticket from place A to place B be 'x' and the cost from place A to place C be 'y'.
From the data given, we can form the following equations:
3x + 1y = 405 -------(1)
2x + 3y = 620 -------(2)
Multiplying the first equation by 3, we get
9x + 3y = 1215 --------(3)
Subtracting (2) from (3), we get
7x = 1215-620
7x = 595
x= 85
Substituting the value of x in (1), we get
3(85) + y = 405
y = 405 - 255
y= 150
Thus, the bus fare for travelling from A to B is Rs. 85 and the fare from A to C is Rs. 150.
sahil939:
thx
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