Question

one pipe can fill a pool 1.25 times as fast as a second pipe. when both pipes are opened they will fill the poll in 5 hours.how long would it take to fill the pool if onle the slower pipe is opened?​

Answer 1

Answer:

11.25Y /Y=11.25

Step-by-step explanation:

Answer 2

The time taken by the slower pipe to fill the pool = 11.25 hours.

Explanation:

Let x be time taken by the slower pipe to fill the pool.

Then, the time taken by the faster pipe yo fill the pool = $\dfrac{x}{1.25}=\dfrac{100x}{125}=\dfrac{4x}{5}$

As per given  , we have

$\dfrac{1}{x}+\dfrac{1}{\dfrac{4x}{5}}=\dfrac{1}{5}\\\\ \dfrac{1}{x}+\dfrac{5}{4x}=\dfrac{1}{5}\\\\ \dfrac{4+5}{4x}=\dfrac{1}{5}\\\\ \dfrac{9}{4x}=\dfrac{1}{5}\\\\ x=\dfrac{9\times5}{4}=11.25$

Hence, the time taken by the slower pipe to fill the pool = 11.25 hours.

#Learn more :

A swimming pool is filled by 3 pipes with uniform flow. First two pipes operating

simultaneously, fill the pool in the same time during which the pool is filled by the third pipe

alone. Second pipe fills the pool 5 hrs. faster than the first pipe and 4 hrs. slower

than the third pipe. Find the time required by each pipe to fill the pool separately.​

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