One pipe can fill a tank in (x-2)hrs and the other pipe can empty the pipe in (x+2)hrs.If the tank is empty and both the pipes are opened together ,the tank is filled completely in 24 hrs.Find out how much time will second pipe take to empty the tank ?
Answers
Answered by
1
It will take 28 hours to empty the tank woth second pipe.
Answered by
2
Answer:
=> Suppose that volume of the tank is A liters…
First pipe can fill the tank in x–2 hours…
So…
In one hour the Volume filled in by one pipe is…
Volume (In) = A/x–2
Second pipe can fill the tank in x+2 hours…
So…
In one hour the Volume emptied out by second pipe is…
Volume (Out) = A/x+2
If the tank is empty and both the pipes are opened together…
In 1 hour the total volume of the tank will be…
Volume (In) – Volume (Out)
= [(A/x–2)–(A/x+2)]
So, in 24 hours the total volume of the tank will be…
24[(A/x–2)–(A/x+2)]
= 24 × 4/(x² – 4) = 1
= x² – 4 = 96
= x² = 100
∴ x = 10
Filled in time is 10 – 2 = 8 hour.
Emptied out time is 10 + 2 = 12 hour.
Hence time taken by second pipe to empty the tank is...
x+2,
= 10+2 = 12 hrs. ans
Step-by-step explanation:
Plz follow me dear and thnks my ans multiple times ...
Similar questions