Question

One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe can fill the tank in 36 minutes, then slower pipe alone would be able to fill the tank in how much time ?​

Answer 1

Answer:

Let the slower pipe alone fill the tank in x minutes.

Then, faster pipe will fill it in 3x minuts.

∴x1+x3=361

⇒x4=361

⇒x=144 min.

Answer 2

Answer:

$\huge\underline\bold {Answer:}$

Suppose the faster pipe A can fill the tank in x minutes. Then,

Slower pipe B will fill it in 3x minutes.

In one minute both the pipes can fill

$\frac{1}{x} + \frac{1}{3x} = \frac{4}{3x} \: of \: the \: tank$

Also, given that in one minute both the pipes can fill 1/36 of the tank.

Therefore, 4/3x = 1/36

=> x = 48.

Hence, the slower pipe will take 3 × 48

= 144 minutes.