Question

One pipe can fill atank in 5 hours less than another.together they can fill the tank in 6 hrs. How long it will take to fill the tank alone

Answer 1

Answer:

6 hours

Step-by-step explanation:

then the pipe B fill the tank in (x-6) hours.

In one hour, the pipe A fills 1/x part of the tank.

And,in one hour the pipe B fills 1/(x-6) part of the tank.

So both pipes together fill 1/x+1/(x-6) part of the tank in one hour.

In one hour, both pipes together fill [x+x-6]/x(x-6) part of the tank.

Time taken to fill the tank is x(x-6)/(2x-6)= 4

 

x^2-6x = 8x-24

x^2-14x+24 = 0

(x-2)(x-12) = 0

x = 2 or 12

X cannot be equal to 2.

So, x = 12

So the pipe A fill the tank in 12 hours.

Then the pipe B fill the tank in (12-6)= 6 hours.