Question

one plus 2 power of minus one plus 3 power of minus 1 plus 4 power of 0​

Answer 1

Answer:

$\huge \fcolorbox{black}{cyan}{♛answer♛} \\ {(1 + 2)}^{ - 1} \times {(1 + 3)}^{ - 1} + {4}^{0} \\ = {3}^{ - 1} \times {4}^{ - 1} + 1 \\ = \frac{1}{3} \times \frac{1}{4} + 1 \\ = \frac{1}{12} + 1 \\ = \frac{1 + 12}{12} \\ = \frac{13}{12}$