Question

One projectile moving with velocity v in space, gets burst into 2 parts of masses in the ratio 1:2. the smaller part becomes stationary. what is the velocity of the other part ? a. 4v b. v c. 4v/3 d. 2v/3

Answer 1

Given:

One projectile moving with velocity v in space, gets burst into 2 parts of masses in the ratio 1:2. the smaller part becomes stationary.

To find:

Velocity of larger part.

Calculation:

Let total mass of Projectile be m,

So, mass of small part is m/3 and that of larger part is 2m/3.

Let Velocity of larger part be u;

Now , applying Conservation of Momentum:

$\rm{ \therefore \: Initial \: P = final \: P}$

$\rm{ = > \: mv=( \dfrac{m}{3} \times 0) + ( \dfrac{2m}{3} \times u)}$

$\rm{ = > \: mv=( 0) + ( \dfrac{2m}{3} \times u)}$

$\rm{ = > \: mv= \dfrac{2m}{3} \times u}$

$\rm{ = > \: v= \dfrac{2}{3} \times u}$

$\rm{ = > \: v= \dfrac{2u}{3} }$

$\rm{ = > \: u= \dfrac{3v}{2} }$

So, final answer is:

$\boxed{ \rm{ \: velocity \: of \: larger \: part= \dfrac{3v}{2} }}$

Answer 2

Explanation:

3v/2 ..............................