Question

One red flower, three white flowers and two blue flowers are arranged in a line such that i. No two adjacent flowers are of the same colour. Ii. The flowers at the two ends of the line are of different colours. In how many different ways can the flowers be arranged?Select one:

Answer 1

Answer:

the flowers can be arranged in 6 Ways

Step-by-step explanation:

One red flower, three white flowers and two blue flowers are arranged in a line such that i. No two adjacent flowers are of the same colour.

White Flowers = 3

Red Flowers = 1

Blue Flowers = 2

Total FLowers = 6

The flowers at the two ends of the line are of different colours

=>  White Flowers can have either

1  , 3  , 5  Position  or  2 , 4 , 6

=> 2 Ways

Then in each case 3 positions Left and Red flower can take one position out of these three

And then remaining positions has to be taken by blue

=> 3 * 2 = 6 Ways

the flowers can be arranged in 6 Ways