One regular polygon has twice as many sides as another and the angle
of the first to that of the second is in the ratio 5:4, then number of sides
in each polygon is
Answers
Answered by
2
Answer:
the interior angles of an n-gon are
(n-2)(180)/n
So, you have
((2n-2)/(2n)) / ((n-2)/n) = 5/4
Now just solve for n.
pls Mark as brainlest...
Answered by
0
the interior angles of an n-gon are
(n-2)(180)/n
So, you have
((2n-2)/(2n)) / ((n-2)/n) = 5/4
Now just solve for n
(n-2)(180)/n
So, you have
((2n-2)/(2n)) / ((n-2)/n) = 5/4
Now just solve for n
Similar questions