Question

One room of a school is 6m long and 4m broad How many tiles of length 50cm and breadth 40cm will be required to cover the floor. What will be the total cost at ₹4.50 per tile?​

Answer 1

Step-by-step explanation:

Given, Length of room =4.5m and breadth of room =4 m

So, Area of room =4.5×4=18 m

2

Area of room =18×(10000 cm

2

)=180000cm

2

Size of tiles =(15 cm×10 cm)

So, Area of tile one =15×10=150 cm

2

So, number of tiles required to cover the floor=

Area of one tile

Area of floor

=

150

180000

=1200

It is given that for one tile it costs Rs. 4.50

Therefore. cost of covering the floor with tiles

=4.50×1200=Rs.5400

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Answer 2

Answer:

Answer is Rs. 540

Step-by-step explanation:

Length of room = 6m

Breadth of room =4 m

Then area =l×b

6 ×4=24m^2

Then area of one tile is

50/100×40/100 =1/2×2/5=1/5

Then no. Of tiles required in 24m^2 area =

24=1/5

=120 tiles

Cost of one tile is 4.50

Then.

Cost of 120 tiles is =120×4.50

rupees 540.

Total cost of tiles is Rs. 540

Thank you