Question

one root of equation 2x^2 +px-16=0 is 2, then the other root is _______​

Answer 1

Answer:

Since x=2 is a root of the equation

2x ^2 +px−6=0

2p+2=0

k=−1

Putting p=-1 in the given equation, we get,

2x^ 2 −x−6=0

(x−2)(2x+3)=0

x=2,− 23

Hence, the other root is − 23

Answer 2

Answer:

Other root is- 4.

Step-by-step explanation:

2x^2+px-16=0

One root is 2, then put x=2

2×2×2+p2-16=0

8-16+p2=0

2p=8

Then, p - 4

Other root is - 4

Thank you.