One root of equation a(b-c)y2+b(c-a)y+c(a-b)= 0 is 1 then other root
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let p&q are two roots of eqn
p×q=c(a-b)/a(b-c)=(ac-bc)/(ab-ac)
p×q=c(a-b)/a(b-c)=(ac-bc)/(ab-ac)
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