Question

one root of the equation 3 x square - 3 x + 3 equal to zero is 1 by 3 find the other route

Answer 1

3x^2 - 3x + 3 = 0

Sum of roots = - b/a

=> alpha + beta = - (-3)/3

=>alpha + 1/3 = 1

=> alpha = 1 - 1/3

=> alpha = 2/3

Other root = 2/3

Answer 2

Hay dear



3x²-3x+3 = 0


Now, sums of root



$\frac{ - b}{a}$


$\alpha + \beta = - \frac{ (- 3)}{1}$


$\alpha + \frac{1}{3} = 1$


$\alpha = 1 - \frac{1}{3}$


$\alpha = \frac{2}{3}$




I hope it's help you