Question

one root of the equation x²+12x-k=0 is thrice the others find the value of k

Answer 1

Heyy mate ❤✌✌❤

Here's your Answer.....

⤵️⤵️⤵️⤵️⤵️⤵️⤵️⤵️

Given;

x^2 +12x - k = 0.

one root is thrice the other
Let one root be =α

Other root=β

3β=α

As this is a quadratic equation thus the sum of roots will be

α+β= -b/a

α+ 3α= -12/1

4α= -12

α= -3

Thus one root is -3

Putting the value of -3 in the polynomial
x^2 +12x -K

(-3)^2 +12(-3) -K=0

9 -36 -K=0

-27 -K=0

K=27
✔✔✔

Answer 2

✨Hey mate
✨
Here is ur answer ⤵️⤵️

Given equation = x^2 +12x -K
Also given = one root is thrice the other
Let one root be =α
Other root=β
3β=α
As this is a quadratic equation thus the sum of roots will be
α+β= -b/a
α+ 3α= -12/1
4α= -12
α= -3
Thus one root is -3
Putting the value of -3 in the polynomial
x^2 +12x -K
(-3)^2 +12(-3) -K=0
9 -36 -K=0
-27 -K=0
K=27