Question

One root of the polynomial f(x) = bx^2 +13x +5 is reciprocal of the other then the value of b is

Answer 1

Hey

Here is your answer,

bx^2 + 13x + 5 = 0

Let the roots of the equation be alpha and 1/alpha.

Product of zeroes = c/a
Alpha x 1/alpha = 5/b
1 = 5/b
b = 5

Hope it helps you!

Answer 2

bx² + 13x + 5


here,

a = b , b = 13 and c = 5.


product of zeroes = c/a

ß × 1/ß = 5/b


b = 5