One root of the quadratic eqn 2x^2 - 8x - k =0 is 5/2. find the other root and value of k
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2
let the other root be y
si y+5/2= 4
=>y = 3/2
and , 3/2*5/2=k/2
=> k = 15/2
si y+5/2= 4
=>y = 3/2
and , 3/2*5/2=k/2
=> k = 15/2
muskan16411:
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Answered by
1
When we put value of x as 5/2 then it will give 0 as resultant.
2x² - 8x - k = 0



- 15 - 2k = 0
k = - 15 / 2
2x² - 8x - k = 0
- 15 - 2k = 0
k = - 15 / 2
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