One root of the quadratic equation (2x-3) (x+5)=0 is -5, then the other root is
A. 5 B.
3
2
−
C. 3
2
D. 2
Answers
Answered by
6
Answer:
2x3−6x2−3x+5
sum of roots of cubic equation ax3+bx2+cx+dis −b/a
therefore sum of roots will be -(-6)/2=3
we can check the answer by finding the roots and adding them
roots of this equation are −1,2+6√2,2−6√2
which add upto 3 so our answer is correct
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