Question

One root of the quadratic equation (2x-3) (x+5)=0 is -5, then the other root is

A. 5 B.

3

2

−

C. 3

2

D. 2B.-3C.3ttt unprecedented mt wind b do off
$\\ \\ \\ \\ \\ \\ \\ . |002284y {0yy1.2 \times \frac{?}{?} }^{?} | 24. | = - \\ \\ < + y5625 \frac{ {) < + 00 |12| \times \frac{?}{?} }^{2} }{?} | \times \frac{?}{?}$
er uc pyrbye​

Answer 1

(2x-3) (x+5) =0

(2x-3) =0

2x=3

x=3/2

Answer 2

Answer:

(2x-3) (x+5)=0

(2x-3)=0

2x=3

x=3/2