Question

One root of the quadratic equation xsquare +(3-2a)x-6a=0;find its other root

Pls ans fast

Answer 1

Answer:

The required roots are -3 and 2a

Step-by-step explanation:

I have applied factorizaation method to solve this quadratic equation.

$x^2+(3-2a)x-6a=0$

$x^2+3x-2ax-6a=0$

$x(x+3)-2a(x+3)=0$

$(x+3)(x-2a)=0$

x+3=0 or x-2a=0

x = -3, 2a

The required roots are -3 and 2a

Answer 2

The roots of the equation are -3 and 2a.

Step-by-step explanation:

Given : Equation $x^2+(3-2a)x-6a=0$

To find : The roots of the equation ?

Solution :

Quadratic equation $x^2+(3-2a)x-6a=0$

Open the middle bracket,

$x^2+3x-2ax-6a=0$

$x(x+3)-2a(x+3)=0$

$(x+3)(x-2a)=0$

$x+3=0$ or $x-2a=0$

$x = -3, 2a$

Therefore, the roots of the equation are -3 and 2a.

#Learn more

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