Question

One's place of a two digit number is three times of ten's place number. If you interchange the digits of this two digit number and add the resulting number to the original number,you get 13. What is the original number?

Answer 1

Answer:

Step-by-step explanation:

let initial number be xy

reversed number :yx

given y=3*x

10y+x+10x+y=13

11x+11y=13

x+y=13/11

4x=13/11

x=13/44

i strongly feel question has some missing element