One set containing 5 numbers has mean =8and variance =24 and the second set contains 3 number has mean=8 and variance=24. The variance of combined set is?
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Answer:
24
Step-by-step explanation:
One set containing 5 numbers has mean =8and variance =24 and the second set contains 3 number has mean=8 and variance=24. The variance of combined set is?
n₁ = 5 , X₁ = 8 , σ₁ = 24
n₂ = 3 , X₂ = 8 , σ₂ = 24
Combined Mean = Xc
Xc = (n₁ X₁ + n₂X₂)/(n₁ + n₂) = (5 * 8 + 3*8)/(5 + 3) = 8
Combined Variance = σc
σc = ( n₁(σ₁ + (X₁-Xc)²) + n₂(σ₂ + (X₂-Xc)²) ) /(n₁ + n₂)
=> σc = ( 5 ( 24 + (8-8)² + 3(24 + (8-8)²) )/(5 + 3)
=> σc = (5 * 24 + 3 * 24)/8
=> σc = (8 * 24)/8
=> σc = 24
The variance of combined set is 24
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