one side in equilateral triangle measuring 8 cm find its area using heron's formula what is its altitude
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a= 8cm b= 8cm c= 8cm
semi- perimeter = a+b+c÷2
= 8+8+8÷2 = 24 ÷ 2 = 16 cm
Area = ✓16(16-8) (16-8) (16-8)
= ✓16× 8×8×8
= ✓2×2×2×2×2×2×2×2×2×2
= 32 cm sq.
Area of triangle = 1÷2 × b×h
32 × 2÷8 = h
8cm= h
semi- perimeter = a+b+c÷2
= 8+8+8÷2 = 24 ÷ 2 = 16 cm
Area = ✓16(16-8) (16-8) (16-8)
= ✓16× 8×8×8
= ✓2×2×2×2×2×2×2×2×2×2
= 32 cm sq.
Area of triangle = 1÷2 × b×h
32 × 2÷8 = h
8cm= h
rashmiverma:
my answer is wrong so please correct me
give answer
ur calculations are incorrect
32÷8 gives 4 then u have to multiply it with 2 so 4×2 = 8cm
it cannot be 128 as height is always smaller than area.
so have a check on ur calculations.
but your question is saying 32×2÷8 ok and then you say 32 x 8
i had not said 32×8 u r not getting that
plzz calculate correctly
OK
Answered by
1
Answer:
⇒ Area = 4√48 cm²
Step-by-step explanation:
We know that all side of an equilateral triangle are equal. Hence some of their side here will be 8 + 8 + 8 = 24 cm
So , Perimeter = 24 cm
We have,
⇒ 2s = 24 cm
⇒ s = 12 cm
Therefore,
⇒ Area = √s ( s - a ) ( s - b ) ( s - c )
⇒ Area = √12 ( 12 - 8 ) ( 12 - 8 ) ( 12 - 8 )
⇒ Area = √12 × 4 × 4 × 4
⇒ Area = 4√48 cm²
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