Question

One side of a cube box is 0.5 m How much will it cost to

paint the outer surface of the box at the rate of Rs 40 per

sq.m.?

Solution

In a ______:

Side = 0.5 m

TSA = ______ (formula)

TSA = 6 x ____ x ______ = ______ sq m.

Cost of 1 sq.m – Rs 40.

Cost of painting 1.50 sq. m = _____ x ______ = Rs. _______.​

Answer 1

In a cube :

Side = 0.5 m

TSA = 6 × l × l (formula)

TSA = 6 x 0.5 x 0.5 = 1.50 sq m.

Cost of 1 sq.m – Rs 40.

Cost of painting 1.50 sq. m = 1.50 x 40

= Rs. 60 .

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Answer 2

Answer:

The cost of painting 1.50 sq.m will be Rs. 60.

Step-by-step explanation:

In a cube:

Step 1:-

Let side be (s) = 0.5 m

TSA = 6s²   [ the formula of total surface area of a cube is 6a², where a is the length of the cube ]

⇒ TSA = 6 x 0.5 x 0.5 = 1.50 sq m. [ according to the question s = 0.5 ]

Step 2:-

∵ Cost of 1 sq.m = Rs 40.

∴ Cost of painting 1.50 sq. m = 1.50 x 40 = Rs. 60.​

Hence, the cost of painting 1.50 sq.m will be Rs. 60.

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