one side of a die is painted white, two sides are painted black and remaining sides are painted red. If this die is tossed twice ,then the probability that both the times we get red side is ?
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Hi may be the answer is 6/36 =>
1/6.
1/6.
darshil7:
its ans. is 1/4
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Since the die is tossed twice, therefore
White=2
Black=4
Red=6
Total Number of Possible Outcomes = 1+2+3
=6
Since dice is tossed twice, therefore outcomes=6×2=12
Favourable outcomes for both times getting red = 6/12=1/2
White=2
Black=4
Red=6
Total Number of Possible Outcomes = 1+2+3
=6
Since dice is tossed twice, therefore outcomes=6×2=12
Favourable outcomes for both times getting red = 6/12=1/2
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