one side of a parallelogram is 2.5 m longer than its adjacent side if the perimeter of a parallelogram is 51 metre find the measure of all its sides
Answers
Let ABCD is a parallelogram
Let ABCD is a parallelogramLet AB=x m
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) m
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5⇒51=4x+5
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5⇒51=4x+5⇒4x=51−5
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5⇒51=4x+5⇒4x=51−5⇒4x=46
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5⇒51=4x+5⇒4x=51−5⇒4x=46⇒x=
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5⇒51=4x+5⇒4x=51−5⇒4x=46⇒x= 4
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5⇒51=4x+5⇒4x=51−5⇒4x=46⇒x= 446
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5⇒51=4x+5⇒4x=51−5⇒4x=46⇒x= 446
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5⇒51=4x+5⇒4x=51−5⇒4x=46⇒x= 446
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5⇒51=4x+5⇒4x=51−5⇒4x=46⇒x= 446 ⇒x=11.5 m
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5⇒51=4x+5⇒4x=51−5⇒4x=46⇒x= 446 ⇒x=11.5 mSo,
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5⇒51=4x+5⇒4x=51−5⇒4x=46⇒x= 446 ⇒x=11.5 mSo, AB=CD=11.5 m
Let ABCD is a parallelogramLet AB=x mAdjacent side BC=(x+2.5) mNow,CD=AB=x m [Opposite sides of parallelogram are equal]And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]Perimeter =AB+BC+CD+AD⇒51=x+x+2.5+x+x+2.5⇒51=4x+5⇒4x=51−5⇒4x=46⇒x= 446 ⇒x=11.5 mSo, AB=CD=11.5 mand BC=AD=11.5+2.5=14 m
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