one side of a parallelogram is 4m longer than its adjacent side. if the perimeter of the parallelogram is 68m, find the measure of all sides
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Step-by-step explanation:
Let ABCD is a parallelogram
Let AB=x m
Adjacent side BC=(x+2.5) m
Now,
CD=AB=x m [Opposite sides of parallelogram are equal]
And AD=BC=(x+2.5) m [Opposite sides of parallelogram are equal]
Perimeter =AB+BC+CD+AD
⇒51=x+x+2.5+x+x+2.5
⇒51=4x+5
⇒4x=51−5
⇒4x=46
⇒x=
4
46
⇒x=11.5 m
So,
AB=CD=11.5 m
and BC=AD=11.5+2.5=14 m
Answered by
0
Step-by-step explanation:
let ABCD be a parallelogram
let AB be x m
Adjecent side BC=(x+4 m)
Now,
CD=AB=x m. [opposite side of parallelogram are equal]
And, AD=BC=(x+4 m). [opposite side of parallelogram are equal]
perimeter =AB+BC+AD+CD
68=x+x+4+x+x+4
68=4x+8
4x=68-8
4x=60
x=60/4
x=15 m
so,
AB=CD=15 m
And BC=AD=15+4=19 m
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