Question

One side of a rectangle exceeds it's other side by3 meter . If the area of the rectangle is 238metre square determine the sides of rectangle

Answer 1

Step-by-step explanation:

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so let the one side of rectangle ie its length be l m also its other side ie its breadth be b m

so according to first condition

l=b+3 (1)

now we know that area of rectangle=l×b

so according to second condition

lb=238

so b(b+3)=238 from (1)

ie b square+3b=238

so b square+3b-238=0

so b square+17b-14h-238=0

ie b(b+17)-14(b+17)=0

(b-14)(b+17)=0

ie b=14 or b=-17

but as dimensions length are never negative

b-17 is absurd

thus b=14

so substitute value of b in (1)

we get l=17

hence length of above rectangle is 17m and it's breadth is 14m