Math, asked by binti44, 8 months ago

One side of a rectangle is 4 cm and the other side 5/2 is times the given side. Find the perimeter
of the rectangle​

Answers

Answered by TheMoonlìghtPhoenix
19

Answer:

Step-by-step explanation:

ANSWER:-

Given that:-

  • One side of rectangle :- 4 cm
  • Other side - 5/2 times other side.
  • Perimeter we need to find.

To find the other area:-

\sf{\dfrac{5}{2} \times 4}

\sf{= 10 cm} is the other side.

Now , we know that:-

\boxed{\bf{Perimeter \ of \ Rectangle = 2 \times (Length+Breadth)}}

  • Where length is 4 cm
  • Where breadth, we found is 10 cm.

Placing the values, we get

\bf{Perimeter = 2 \times (10+4)}

\bf{Perimeter = 2 \times 14}

\boxed{\sf{Perimeter = 28 cm}}

What if said to find the area?

We know that:-

\boxed{\sf{Area \ of \ Rectangle = Length \times Breadth}}

So,

\sf{Area = 10 \times 4 }

\boxed{\sf{Area = 40 cm^2}}

Answered by Anonymous
36

 \orange{ \sf{ How \: to \: solve?}}

Here, we know that one side of a rectangle is 4 cm and Let us take this one side as length. Again, we know that the other side is  \frac{5}{2} times the given side. So by multiplying  \frac{5}{2}  with 4 cm, We will get other side and let us now take other side as breadth. Now we come to know length as well as breadth. Thus, by using formula we will find perimeter of the rectangle.

 \huge{ \gray{ \underline{ \underline{ \tt{ \red{S} \purple{ol} \pink{u} \orange{ti} \green{on}}}}}}

{ \green{ \underline{ \underline{ \rm{ \orange{Given :}}}}}}

\green{ \small{ \rm{One \: side \: of \: a \: rectangle = 4 \: cm}}}

 \green{ \small{ \rm{Other \: side \: of \: a \: rectangle =  \frac{5}{2} \times 1st \: side}}}

 \green{ \underline{ \underline{ \rm{ \orange{To \: Find :}}}}}

 \green{ \small{ \rm{Perimeter \: of \: a \: rectangle.}}}

 \green{ \underline{ \underline{ \rm{ \orange{Let's \: Find \: out :}}}}}

{ \green{ \small{ \rm{One \: side = 4 \: cm}}}}

{ \green{ \small{ \rm{Other \: side =  \frac{5}{2}  \times One \: side}}}}

 \green{ \small{ \rm{ =  \frac{5}{2}  \times 4}}}

{ \green{ \small{ \rm{ =   {\frac{5} {\cancel{2}}}  \times  {\cancel{4} = 10 \: cm }}}}}

Let the length = 4 cm and breadth = 10 cm.

Now,

 \green{ \small{  \underline{ \boxed{ \sf{ \orange{Perimeter \: of \: rectangle = 2(l + b)}}}}}}

Here,

 \green{ \small{ \rm{l = 4 \: cm \: , \: b =10 \: cm }}}

 \green{ \small{ \rm{Perimeter = 2(4 + 10) = 2(14) = 28 \: cm}}}

Hence,

{ \green{ \underline{ \overline{ \boxed{ \rm{ \orange{Perimeter \: of \: rectangle = 28 \: cm}}}}}}}

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