Question

One side of a rectangle is five times as long as the other side. If the perimeter is 72 meters, what is the length of the shorter side?

Answer 1

Let the longer side be x ( l )
and smaller side be y ( b )

x = 5y ...... ( i )

Perimeter :- 2 ( l + b )

72 = 2 ( x + y )

36 = ( 5y + y )

36 = 6y

6 = y


Putting this in ( i )

x = 5y

x = 30

Length ( larger side ) :- 30m

Breadth ( smaller side ) :- 6 m

Answer 2

Concept introduction:

Any two-dimensional creature's perimeter is determined by the space surrounding it. By summing the lengths of the sides, we can get the perimeter of any closed form.

Given:

Here it is given that one side of a rectangle is five times as long as the other side and the perimeter is $72$ meters.

To find:

We have to find the length of the shorter side.

Solution:

According to the question,

Let the longer side be $x ( l )$

and smaller side be $y ( b )$

$x = 5y ...... ( i )$

Perimeter :$- 2 ( l + b )$

$72 = 2 ( x + y )36 = ( 5y + y )36 = 6y6 = y$

The length is $6m$.

Putting this in $( i )$

$x = 5y\\x = 30$

Final answer:

The final answer of the length of shorter side is $6m$.

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