One side of a rectangle lies along the line 4x + 7y + 5 = 0. Two of its
vertices are (–3, 1) and (1,1). Find the equation of other three sides.
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if 4x+7y+5=0
so put (-3,1) at the place x and y
than we got
4×(-3)×+7×1+5=0
-12+12=0
0=0
and when we put(1,1) at the place of x and y
4×1+7×1+5=0
16=0
so equation is write when we put (-3,1) at the place of x and y
so put (-3,1) at the place x and y
than we got
4×(-3)×+7×1+5=0
-12+12=0
0=0
and when we put(1,1) at the place of x and y
4×1+7×1+5=0
16=0
so equation is write when we put (-3,1) at the place of x and y
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