One side of a rectanglular garden is 48m and its diagonal is 50 m long.Find the area and perimeter of the garden
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let the length be 48m and breadth be b
by pythagoras theorem
48²+b²=50²
2304+b²=2500
b²=2500-2304
b²=196
b=14m
perimeter=2(l+b)
P=2(48+14)
P=2(62)
P=124m
Area=l×b
A=48×14
A=672m²
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