Question

One side of a rectangular field is 15 m and one of its diagonals is 17 m. Find the area of the field.​

Answer 1

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Answer 2

$\bf{\underline{Question:-}}$

One side of a rectangular field is 15 m and one of its diagonals is 17 m. Find the area of the field.

$\bf{\underline{Solution:-}}$

Let,

• the rectangle be ABCD
• Let BC = 15m
• diagonal ,AC = 17 m

By applying Pythagoras theorem,

• AC² = AB² + BC²

$\bf ⇒ AB^2 = AC²-BC²$

$\bf ⇒ AB^2= 17^2-15^2$

$\bf ⇒AB^2 = 289 - 225$

$\bf ⇒ AB^2 = 64$

$\bf ⇒ AB= \sqrt{64}$

$\bf ⇒AB = 8m$

$\bf{\underline{Therefore:-}}$

• Area of rectangle = length × breadth
• Area of rectangle = 15 × 8 = 120 m²