Question

one side of a rectangular garden is 48 m and its digonal is 50 long. find the area and perimeter of the garden​

Answer 1

Answer:

area =48x50 =2400

perimeter=2(l+b)

perimeter =4800

Answer 2

Step-by-step explanation:

All angles of rectangle are of 90°

By right angled ∆ theorem,

hypotenuse^2 = l^2 + b^2

50^2 = 48^2 + b^2 -----( diagonal of rectangle is considered as hypotenuse )

2500 = 2304 + b^2

2500 - 2304 = b^2

196 = b^2

√196 = b

14 m. = b

Perimeter of rectangle = 2l + 2b

= 2× 48 + 2× 14

= 124 m.

Area of rectangle = l×b

= 48×14

= 672 sq.m.