Question

one side of a rhombus is 10 cm and one of its diagonal is 16 cm .the area of the rhombus is .​

Answer 1

Answer:

Step-by-step explanation:

Hope you understand

Answer 2

Answer:

96 sq. cm

Step-by-step explanation:

Diagonals of a rhombus bisect each other at right angles.

Let ABCD be the rhombus, Diagonal AC= 16 cm and side AB = 10 cm.

In right triangle AOB, AB = 10 cm, AO = 8 cm

By Pythagoras theorem, AB2 = AO2 + BO2

=> (10)2 = (8)2 + BO2

=> BO2 = (10)2 – (8)2

=> BO = 6 cm

=> Diagonal BD = 2 x 6 = 12 cm

Area of rhombus = 1/2 × pro. of its diagonal

= 1/2 × 16 × 12

= 96 sq. cm

Hence the area of the rhombus is 96 sq cm .

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